Interested in joining a growing organization? We're hiring! Check out our website for more information. https://lnkd.in/g6_EP3ya
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*Psychotherapist *Master IEP Coach® *Published Author *Public Speaker *Professional Development (MH/SA/Autism)
Feel free to click on the link below to learn more about the Tailored Care Management position opening. Or feel free to inbox me with questions. Tailored Care Management is an awesome opportunity to serve those with mental health/substance use struggles ❤️💚 #tailoredcaremanagement #integratedfamilyservices #mentalhealth #substanceuse #wholepersoncare
Join Our Team - We are searching for a Full-Time Care Manager! Through Tailored Care Management, Behavioral Health Tailored Plan beneficiaries will have a designated care manager supported by a multidisciplinary care team to provide whole-person care management that addresses all their needs, spanning physical health, behavioral health, pharmacy, and unmet health related resource needs. To learn more & apply ⬇️ https://lnkd.in/ev9Knr5d
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Are you brave enough to take on the challenge of leading policy work to ensure the world's next innovations and ideas get to market or into policy? If so, consider this job working with Jane Ryan and the team at DASSH | Deans of Arts, Social Sciences and Humanities. I may be on the STEM side of the sector these days, but I know all too well that STEM is only as good as our HASS colleagues; a true ying and yang. The skills from the HASS disciplines helps us understand markets, development effective user interfaces/experiences, develop business models and ensure effective marketing, amongst many, many other considerations. But, we have a policy challenge in our society in understanding and valuing HASS. Lets change this! For example: 1) I remember hearing about a photovoltic scientist who gave innovative flexible cells to design students to work out new and creative use cases, one result was shade clothes with integrated solar for outdoor areas. #createch at its best. 2) Artificial Intelligence is only as good as the user experience (i.e. ChatGPT) and the ways the underlying model's analyse, categorises information and access training datasets. HASS is having its moment to shine! Australian Academy of the Humanities, Academy of the Social Sciences in Australia, Australian Council of Learned Academies (ACOLA), #HASS, #humanities, #socialscience
Come work with DASSH | Deans of Arts, Social Sciences and Humanities! We are looking for a Policy and Communications Officer who will play a key role in achieving DASSH’s goal of increasing its advocacy efforts and research output. This is a part-time permanent role. Applications close June 23. Please share this opportunity with your networks! See full details of the position here: https://lnkd.in/gA8RaBGC
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In case you are interested
Director of Policy and Public Affairs at Royal College of Obstetricians and Gynaecologists | RCOG
WE ARE HIRING! Are you a policy professional, passionate about women's health, and looking for your next opportunity? Here's your chance to join our small but highly impactful team, taking the lead on issues that are central to the wellbeing of women and girls. You'll keep the RCOG at the forefront of debates that affect women’s health, working in partnership with women and RCOG members to develop policy solutions to improve the health of women and girls. Find out more https://lnkd.in/giruYTRj
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Principal Engineer/Manager at Qualcomm (Working on WIFI6, WIFI7 and WIFI8) | IISc | GATE AIR 10 | B.E. University Gold Medalist | Bronze Medalist in Regional Mathematical Olympiad
Clearly it is divisible by 2. Let prove it is divisible by 9. n will be of form 6k+p where p€{0,1,2,3,4,5} Given expression equals 4^(6k+p) +24(6k+p) +14 (4^6)^k*(4^p) +144k+24p+14 =(64)^k*(4^(p+1)) +144k+24p+14 =4^(p+1)+6p+5 (mod9) For p=0, 4^(p+1)+6p+5 (mod9)=0(mod9) For p=1, 4^(p+1)+6p+5 (mod9)=0(mod9) For p=2, 4^(p+1)+6p+5 (mod9)=0(mod9) For p=3, 4^(p+1)+6p+5 (mod9)=0(mod9) For p=4, 4^(p+1)+6p+5 (mod9)=0(mod9) For p=5, 4^(p+1)+6p+5 (mod9)=0(mod9) Hence proved
For all non-negative integers n,
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